he means the accuracy. like if it reads 75mph he may be going around 80 becuase of his bigger wheelsOriginally posted by donutchow@Jun 8 2003, 10:57 AM
what do you mean "difference on my speedometer" like you can go faster now?
he means the accuracy. like if it reads 75mph he may be going around 80 becuase of his bigger wheels [/b][/quote]Originally posted by MrM3+Jun 8 2003, 07:34 PM--></span><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (MrM3 @ Jun 8 2003, 07:34 PM)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin--donutchow@Jun 8 2003, 10:57 AM
what do you mean "difference on my speedometer" like you can go faster now?
or you could do it that way.......Originally posted by SpeedsterBMW@Jun 8 2003, 09:07 PM
the "35" is the percent of the width (235) that would equal the height of the sidwall...so take 19", convert it to mm, take 235*.35 add it to the 19" converted to mm, and thats the overall hiehgt, do it for the orignal set
35% is .35 btw....and that 35 sidewall is the percent in height of the width of the tire, in his case 235....so in his case his sidewall is 82.25mm......id convert that into inches, and add that onto the height of the wheel....Originally posted by Fox@Jun 14 2003, 12:08 AM
the way you guys are finding it is wrong... you are taking the tire width or the wheel size (19" 17" etc) but you have to find the circumference to get the rolling distance.
Step 1: finding total diameter - 19" x 1.35 (35%) = 25.65"
Step 2: finding circumfrence - 25.65 x 3.14 = 80.541" in 1 wheel rotation
so you do that for the old wheel and the new wheel. that gives you the difference. then do ratios of inches to a mile.
yea but you do 1.35 to already include the 19 inches of wheel thats 135%. and its not the percent of the width its the percent of the actual wheel diameter. and even if you were right, which you are not. adding it to the hieght of the wheel will only find total diamter. You still need to find the circumfrence to get the rolling distance of 1 rotation. Stop trying to correct me when you yourself are wrong.35% is .35 btw....and that 35 sidewall is the percent in height of the width of the tire, in his case 235....so in his case his sidewall is 82.25mm......id convert that into inches, and add that onto the height of the wheel....
i hade to correct you 3 times already today...and to further support my theory that a 235/35/19 tire, has a sidewall height of 35% of 235:Originally posted by Fox@Jun 14 2003, 09:00 PM
yea but you do 1.35 to already include the 19 inches of wheel thats 135%. and its not the percent of the width its the percent of the actual wheel diameter. and even if you were right, which you are not. adding it to the hieght of the wheel will only find total diamter. You still need to find the circumfrence to get the rolling distance of 1 rotation. Stop trying to correct me when you yourself are wrong.35% is .35 btw....and that 35 sidewall is the percent in height of the width of the tire, in his case 235....so in his case his sidewall is 82.25mm......id convert that into inches, and add that onto the height of the wheel....
:werd:Originally posted by AZ325Ci@Jun 14 2003, 07:17 PM
Fox, you better check your sources before you post and make a fool out of yourself![]()
speedster is right on this