| Originally posted by e30fanm3@Mar 17 2005, 05:28 PM |
ok show me a diagram on how this twin turbo SC setup went and where you put the CAIs, i dont understand why you would need a CAI with an intercooler since the intercooler will cool the air plenty
ok this is gonna get technical so if you need more info you will prolly have to do some more research. First of all, on this 3000GT the CAI is located down in the front valance below the lights on the passenger side. the air travels up the CAI into the two turbos through a split tube. the turbos spool the air and then send it down into the FMIC which gets cooled from the outside air. the air then travels into the SC where the air goes through the ATWC (air to water core) getting cooled some more then into the manifold. Diagram wise if you need one i can draw you one. LOL ok now for the technical stuff. here is how the cooling works and why you want all the cooling extras as the FMIC will not do the job completely.
THE EATON SC AT 8 PSI WILL ONLY PRODUCE A 70-80 DEGREE DELTA RISE. THE W-T-A IC WILL HAVE AN AMBIENT TEMP MINUS THE WIND-CHILL FACTOR WHILE MOVING. THAT DROPS THE THEORETICAL WATER TEMPS TO 20 BELOW DELTA. IF A 75% EFFICIENCY IC IS USED, THEN 80- 75% OF (100-75 DEGREES) IS A WASH +/- 5 DEGREES. THE SC WILL DO NOTHING AT ALL ONCE THE TURBOS MAKE BOOST, SO THE DELTA RISE WILL BE 0--THATS RIGHT--0, AND ADDING WIND CHILL FACTOR WOULD GIVE A DELTA - 15 DEGREES.
THE TURBOS PRODUCING 17 PSI WILL RAISE TEMPS 175 DEGREES @ 75% A.E., AND THE A-T-A INTERCOOLER (FMIC) AT 65% WILL DROP THAT BY 113 DEGREES. SO NOW YOU WILL HAVE DELTA + 61 DEGREES AT 17 PSI +/- 5 DEGREES. IF YOU ARE MOVING THE A-T-A WILL HAVE THE WIND CHILL FACTOR DROP THE TEMPS ANOTHER 20 DEGREES OR SO, AND THAT MEANS ABOUT DELTA + 40 DEGREES @ 17 PSI. ADD A WATER/ALCOHOL-COOLER SQUIRTER WHICH COULD EASILY DROP 50 DEGREES FROM THAT. NOW THE AIR ENTERING THE ENGINE IS COLDER THAN OUTSIDE AIR.
WITH BOTH AN A-T-A AND AN A-T-W IC. THE A-T-A IS FIRST DROPPING 30 PSI BOOST FROM DELTA + 285 TO DELTA + 100 DEGREES. THE 40 DEGREE ICE-WATER IN THE A-T-W WILL DROP THAT +100 ANOTHER 75%, SO DELTA - 40 AS THE MEDIUM WILL GIVE:
DELTA (85 DEGREES) + 100 =185 DEGREES. 185 + 40 DEGREES (225) X 75% = 169 DEGREES. 185 DEGREES MINUS 169 THAT MEANS DELTA -16 DEGREES AT 30 PSI BOOST(69 DEGREES)
So there you have it. All you could possibly want to know about a twin turbo SC 3000GT and how important cooling is based on temp outside and inside the engine compartment. Again sorry for all the technical stuff but it helps explain.